<div dir="ltr">Hi Jolyon,<div><br></div><div>Sorry for the confusion.</div><div><br></div><div>I mean add each operand of the assembler code corresponding to certain value of cpu cycles together to get a rough idea.</div><div>
<br></div><div>Div is far more dear than plus for sure :-)</div><div><br></div><div>Of course take care of condition jump/jump as this will multiple the figures depends on how many jump it will be. </div><div><br></div><div>
Regards</div><div>Leigh</div></div><div class="gmail_extra"><br><br><div class="gmail_quote">On 18 August 2014 09:11, Jolyon Smith <span dir="ltr"><<a href="mailto:jsmith@deltics.co.nz" target="_blank">jsmith@deltics.co.nz</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><div dir="ltr">Leigh, I'm not sure that this would be a reliable indicator of performance. Surely some opcodes are more "expensive" than others ? The relationship between opcodes and CPU cycles is not 1:1 afaik.<br>
</div><div class="gmail_extra"><br><br><div class="gmail_quote"><div><div class="h5">On 18 August 2014 08:51, Leigh Wanstead <span dir="ltr"><<a href="mailto:leigh.wanstead@gmail.com" target="_blank">leigh.wanstead@gmail.com</a>></span> wrote:<br>
</div></div><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><div><div class="h5"><div dir="ltr">Just one suggestion, why not look at assembler code in delphi to count the lines and add up the operands to get the cpu cycle total number? :-)<div>
<br></div><div>My 2 nz cents</div><span><font color="#888888"><div><br></div><div>Leigh</div>
</font></span></div>
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