[DUG] C code help

[Brian Wrigley]

That's the bitwise shift-left operator. So, 0 shifted left 1 bit is still zero, 1 shifted left 1 bit is 2. 1 shifted left 30 bits would be (hex) 40000000.

Brian
  ----- Original Message ----- 
  From: Ross Levis 
  To: NZ Borland Developers Group - Delphi List 
  Sent: Thursday, July 13, 2006 6:44 PM
  Subject: [DUG] C code help


  I have very few clues when it comes to C++.  Particularly with things like this which appear to defy logic!  Can some one convert this to Delphi for me please.

  #define TAG_FIELD_FLAG_DATA_TYPE_TEXT_UTF8      (0 << 1)
  #define TAG_FIELD_FLAG_DATA_TYPE_BINARY         (1 << 1)

So TAG_FIELD_FLAG_DATA_TYPE is a one-bit flag stored in the 2nd-rightmost bit of the word, and its possible values are TEXT_UTF8 (value 0) and BINARY (value 1).

  #define APE_TAG_FLAG_CONTAINS_FOOTER            (1 << 30)

  Or is it this?

  const
    TAG_FIELD_FLAG_DATA_TYPE_TEXT_UTF8 = 0; 
    TAG_FIELD_FLAG_DATA_TYPE_BINARY = 1;
    APE_TAG_FLAG_CONTAINS_FOOTER = 30;

  Thanks,
  Ross.


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